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Configuration = 35
cycles = (10 4 1 8 2)(9 6 3 7 5)

a = 2, b = 4, c = 8
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cycles = (10 2)(9 4 7 5 3)(8 1)(6)

a = 4, b = 7, c = 9
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cycles = (10 2)(9 7 3)(8)(6)(5 1)(4)

a = 2, b = 5, c = 10
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cycles = (10 1 2)(9)(8 6 4)(7)(5)(3)

a = 1, b = 2, c = 10
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cycles = (10)(9)(8)(7 5 3)(6)(4)(2)(1)